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23d^2-31d=0
a = 23; b = -31; c = 0;
Δ = b2-4ac
Δ = -312-4·23·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-31}{2*23}=\frac{0}{46} =0 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+31}{2*23}=\frac{62}{46} =1+8/23 $
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